A single-phase AC voltage converter has the following details −
ON time = 6 min, OFF time = 4 min, frequency = 50Hz, and
Voltage source Vo = 110V
Calculate the following.
Triggering angle α
Solution −
T=2×(TON+TOFF)T=2×(TON+TOFF) but f=50Hz,f=50Hz, T=2×(6+4)=20minsT=2×(6+4)=20mins
360∘=20min,360∘=20min, 1min=18∘1min=18∘
Therefore, TOFF=4minTOFF=4min
Then,
α=40.1×1.8=72∘α=40.1×1.8=72∘
Voltage Output
Solution −
V0=(VS×D),whereD=TONTON+TOFF=610=0.6V0=(VS×D),whereD=TONTON+TOFF=610=0.6
TON=6min,TOFF=4min,VS=110VTON=6min,TOFF=4min,VS=110V
V0(VoltageOutput)=VS×D=110×0.6=66Volts
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